Difficulty level:High-school physics.

# Spring and Rope Puzzle A weight is suspended from a fixed support by two springs and some rope as shown in the diagram to the right (click image for larger view). The weight is two Newtons. (If you aren't metric, use pounds and feet instead of Newtons and meters; the problem will work the same.) Each spring is one meter long when unstretched, and it stretches two meters for every Newton of force on it. The rope from B to C is one meter. Like all textbook physics problems, this one uses ideal parts. In particular, the springs and ropes have no mass of their own.

The two-Newton weight stretches each spring by four extra meters, making each spring five meters long in total. So the distance from A to D is five meters of spring plus one meter of rope plus five meters of spring, for a total of eleven meters. Also note that the distance from A to C is six meters, and the distance from B to D is six meters. This is important because we are going to connect seven meters of rope from C to a point near A, and from B to a point near D. Since each rope is longer than the six meter distance, the rope hangs slackly. The new ropes are shown to the left (click image for larger view).

Now here is the question: What happens when you cut the one-meter rope from B to C? This rope is helping hold up the weight, so the weight will fall. How much lower will it be when it comes to rest?